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RegExp in XSLT

Answer 1

A:

These functions are from XPath 2.0 in XSLT 2.0. .NET XSLT is at 1.0 and your xsl namespace reflects that.

AnthonyWJones 2008-12-04 14:01:02

Answer 2

+2 A:

If you are working exclusively in MS XML you can add custom functions written in a .net language of your choice. See the example on MSDN (they use JScript). Then you could use regexes.

However, you should be able to use the starts-with xslt function to do what you need.

Jennifer 2008-12-04 14:02:18

MS' implementation of XSLT doesn't support 2.0 functions. You have to use an external XSLT library like Saxon. More info here: http://stackoverflow.com/questions/94047/are-net-35-xpath-classes-and-methods-xslt-20-compatible

Will 2008-12-04 14:54:47

Answer 3

A:

There is however an outofjail.get() with .net: there's always the possibility of passing a task to an Extension Object.

Not good practice since it's an extension to XSLT, but sometimes you have to go with what works.

annakata 2008-12-04 14:07:16

Answer 4

+3 A:

In case you're performing the transformation with Visual Studio X, where X is not greater than 2008, this would be processed by an XSLT 1.0 processor (.NET's XslCompiledTransform or XslTransform). XSLT 1.0 uses XPath 1.0, not XPath 2.0 and its F & O (Functions and Operations), which only became a W3 Recommendation last year.

You have two options:

Use a compliant XSLT 2.0 processor. If you prefer to stay within the .NET platform, then a suitable choice is Saxon.NET
Just use the XPath 1.0 function starts-with(), which is sufficient to solve the current problem.
The expression: starts-with(., 'P:Interfaces') is evaluated to true() if the string value of the context node starts with the string 'P:Interfaces' and to false() otherwise.

Another Xpath 1.0 function that may come handy for such type of processing is the function contains().

Xpath's 2.0 function ends-with() can be emulated in XPath 1.0 in the following way:

ends-with(s1, s2) ====substring(s1,string-length(s1)-string-length(s2)+1)=s2

where "===" means is "equivalent to".

Here we also used the XPath 1.0 functions substring() and string-length().

Dimitre Novatchev 2008-12-04 14:59:22

Hi! Thanks a lot for your answer!I already done something like you're talking about - I mean XPath 1.0, I use exactly what you said - starts-with(@name, 'T:MyNamespaces.Interfaces') and contains().

abatishchev 2008-12-04 21:21:29

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RegExp in XSLT

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