[zsh] Remove entry from array

Question

Hi,

I want to do sth. like this:

foo=(a b c)
foo-=b
echo $foo # should output "a c"

How can I remove an entry from an array? foo-=b does not work.

The removal should work no matter where the entry is.

Answer 1

foo = (1 2 3)

shift foo

print $foo gives: 2 3

So this removes the first element (is that what you want?)

[edited]

remove the ith element with

foo[$i] =()

instead.

Answer 2

To remove element number $i: a=("${(@)a[1,$i-1]}" "${(@)a[$i+1,$#a]}")

(The simpler construct a=($a[1,$i-1] $a[$i+1,$#a]) also removes empty elements.)

ADDED:

To remove any occurence of b: a=("${(@)a:#b}")
:# is the hieroglyph to remove matching elements; "" and (@) is to operate correctly on arrays even if they contain empty elements.