Why won't this C program pick up escaped backslashes?

Question

I'm doing K&R's Exercise 1-10

Write a program to copy its input to its output, replacing each tab by \t, each backspace by \b and each backslash by \\. This makes tabs and backspaces visible in an unambiguous way.

I came up with this...

#include <stdio.h>

int main () {

    int c;
    printf("\n"); // For readability

    while ((c = getchar()) != EOF) {

        switch (c) {
            case '\t':
                printf("\\t");
                break;
            case '\b':
                printf("\\b");
            case '\\':
                printf("\\");
                break;
            default:
                printf("%c", c);
                break;
        }

    }

}

For some reason, it refuses to touch backslashes. For example, the output from the program when fed a string such as Hello how\ are you? is Hello\thow\ are you? which means it converted the tab OK, but not the backslash.

Am I doing something wrong? Thanks

Update

Sorry was making dinner, only looked back now. This is not homework. I'm a web dev, trying to expand my horizons. I was told the K&R book is the best book to start with.

Answer 1

You should be printing the backslash and its escape.

Currently you're just printing the backslash - here you're escaping the second backslash which would otherwise escape the closing double quote:

printf("\\");

Answer 2

Use printf("\\\\")

Answer 3

You probably want to printf("\\\\");, instead of just printf("\\");.

Answer 4

What does the C compiler do when it finds \\ in the source?