array_push key=>value , how can do it?

Question

Hi , all

I want to push key and value in array , but I can't

$con = mysqli_connect('localhost','root','','wp') or die (mysqli_error('Error:'));

$query = mysqli_query($con,'set names utf8')or die (mysql_error());
$qy = mysqli_query($con,"SELECT ID,post_title FROM wp_posts WHERE post_type='page' AND post_status='publish'")or die (mysql_error());
$arr = array();
while ($row = mysqli_fetch_array($qy)){
$id = "?page_id=".$row['ID'];
$title = $row['post_title'];
$arr[] = $id . "=>" . $title;
array_push($arr, "$id" => "$title");  
}

plz help me ..

thanks ^_^

Answer 1

Do you want to do $arr[$id] = $title? Or do you want this:

if (!isSet($arr[$id])) {
    $arr[$id] = array();
}
$arr[$id][] = $title;

The former will make it so that $arr contains $id=>$title. The latter will make it so that $arr contains $id=>array($title1,$title2,$title3) etc if there are multiples.

Answer 2

Here's what I would do instead:

$arr = array();
while ($row = mysqli_fetch_assoc($qy)){
    $id = $row['ID'];
    $arr[$id] = $row['post_title'];
}

And then when you need to print them:

foreach ($arr as $id => $title) {
    echo "?page_id={$id}'>{$title}</a>";
    // or whatever, depends on how you want to print it
}

Don't store unnecessary information (ie: ?page_id=) in arrays.