views:

68

answers:

2

I'm struggling with some generics. The following is my setup:

interface I<T> { }

[...]
void Add<T>(T obj) where T : I<??> { }

How can I ensure that T in the Add method implements I?

+1  A: 

You need to pass the T parameter to add also.

void Add<TI, TAny>(TI obj) where TI : I<TAny>
Mark H
`TI` is a generic parameter, not a generic itself, so you can't do `TI<TAny>`. Shouldn't your parameter just be `TI`? And your constraint should be `where T : I<TAny>`.
Joe White
+8  A: 

The following signature will allow Add to take any T that implements I<> with any type parameters.

void Add<T,S>(T obj) where T : I<S> {
}

The downside of using this method signature is that type inference doesn't kick in and you have to specify all the type parameters, which looks downright silly:

blah.Add<I<int>, int>(iInstance);

A much simpler approach is to use the below signature:

void Add<T>(I<T> obj) {
}
Igor Zevaka
`void Add<T>(I<T> obj)` did it. Thanks!
Jon List