Really dumb question but, for instance, given:
var $foo = $('<div>bar</div>');
How would I get the '<div>bar</div>' back out?
views:
32answers:
2
A:
Pointy
2010-08-17 23:34:35
nope, this just returns "bar"
longda
2010-08-17 23:41:54
`$otherFoo` is referencing the cloned `$foo`. You would need to traverse up to its parent (the wrapper `<div>`) in order to get its `.html()`.
patrick dw
2010-08-17 23:43:51
oh right; sorry @patrick I make that mistake all the time in actual code!! Fixing post now.
Pointy
2010-08-18 06:04:46
+2
A:
You need to append it to a container, then call .html() on that.
This is because .html() only gives you the content.
Try it out: http://jsfiddle.net/ttYXG/
var $foo = $('<div>bar</div>');
$('<div />').append($foo).html();
patrick dw
2010-08-17 23:35:19
@longda - If needed, you can get rid of the wrapper `<div>` with `$foo.unwrap();`. May not really be necessary since `$foo` still references your original element.
patrick dw
2010-08-17 23:53:55