trouble with xml transformation

Question

Hi, I have an xml that looks something like this

<para>
   text text text
   <b>text</b> text text <i>text</i>
</para>

the objective is to convert this to mediaWiki formatting with ''' for a bold font and so on.

when I write a transformation for this the template match ignores all the text inside the <para> tag and only the the <b>s and the <i>s are converted. i need help.

update: here is what i have tried so far:

this is what i have tried so far.

<xsl:template match="para">
<xsl:apply-templates select="*"/>
</xsl:template>

<xsl:template match="b">
<xsl:text>'''</xsl:text><xsl:value-of select="replace(replace(.,'\s+$',''),'^\s+','')" disable-output-escaping="no"/><xsl:text>'''</xsl:text>
</xsl:template>

<xsl:template match="i">
<xsl:text>''</xsl:text><xsl:value-of select="replace(replace(.,'\s+$',''),'^\s+','')" disable-output-escaping="no"/><xsl:text>''</xsl:text>
</xsl:template>

this is what I used when i tried the text() function.

<xsl:template match="text()">
<xsl:value-of select="." disable-output-escaping="no"/>
</xsl:template>

--update-- in order to not lose the spaces before and after the text block and the bold and italics flags we can also check for spaces before and after the text.

<xsl:template match="text()">
    <xsl:variable name="originalText" select="."/>
    <xsl:if test="starts-with($originalText,' ')">
        <xsl:text> </xsl:text>
    </xsl:if>
    <xsl:value-of select="normalize-space(.)" disable-output-escaping="no"/>
    <xsl:if test="ends-with($originalText,' ')">
        <xsl:text> </xsl:text>
    </xsl:if>
</xsl:template>

Answer 1

when I write a transformation for this the template match ignores all the text inside the tag and only the the <b>s and the <i>s are converted. i need help.

update: here is what i have tried so far:

this is what i have tried so far.

<xsl:template match="para">  
  <xsl:apply-templates select="*"/>  
</xsl:template>

Your problem is exactly in this template. Your codes ignores anything else except element - children. the * abbreviation stands for child::element(). Thus the text-nodes children of para aren't processed at all.

Solution:

Simply remove the above template. Then the built-in XSLT template for element nodes will be selected to process the para element. All it does is <xsl:apply-templates/> and this is an abbreviation for <xsl:apply-templates select="child::node()"/>. This applies templates for every child node (of any type, including text nodes). When the text-node children of para are processed, the built-in XSLT template for text node is selected -- all it does is to copy the text as is.

The transformation now becomes:

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt;
 <xsl:output method="text"/>

    <xsl:template match="b">
        <xsl:text>'''</xsl:text>
        <xsl:value-of select="replace(replace(.,'\s+$',''),'^\s+','')"/>
        <xsl:text>'''</xsl:text>
    </xsl:template>

    <xsl:template match="i">
        <xsl:text>''</xsl:text>
        <xsl:value-of select="replace(replace(.,'\s+$',''),'^\s+','')" />
        <xsl:text>''</xsl:text>
    </xsl:template>
</xsl:stylesheet>

when applied on the provided XML document:

<para>
   text text text
   <b>text</b> text text <i>text</i>
</para>

the result now includes the text node children of para:

   text text text
   '''text''' text text ''text''