Addition of all digits

Question

I want to write a program to add all the digits of the entered number. For example, when I enter 54496 the output must be 5 + 4 + 4 + 9 + 6 = 28.

Answer 1

This is homework, so this is just a (quick maybe buggy) hint.

1) Initialize sum in 0;

sum := 0

2) take the reminder of the division by 10 of the number and add it to sum.

`sum:= sum + number mod 10`

3) update number to the result number divided by 10.

 `number := number div 10`

4) if number > 1 goto 2

  `if (number greater than 1) goto 1`

sum:= sum + number

Answer 2

#include <iostream>
using namespace std;

int main(){

int a;
cin>>a;
int sum=0;
while (a!=0){
sum+= a %10;
a/=10;
}
cout<<"sum is : "<<sum<<endl;




return 0;

}