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Question

Sort NSMutableArray

Answer 1

A:

NSMutableArray* tempArray = [NSMutableArray arrayWithArray:anArray];
[tempArray sortUsingSelector:@selector(caseInsensitiveCompare:)];

I use this in some code? Will this work?

Also, just noticed you are setting the array objects as strings which I'm assuming will also be an issue. Try adding them as NSIntegers or ints... does that work at all?

Thomas Clayson 2010-08-24 13:26:52

The problem is that the questioner is comparing strings in the default manner, which is not a numeric comparison. `caseInsensitiveCompare:` isn't a numeric comparison, either.

Peter Hosey 2010-08-24 19:44:59

hmm, fair enough

Thomas Clayson 2010-08-25 08:26:13

this is my code:[item setObject:[NSNumber numberWithInt:[[[_modeObject valueForKey:@"point"] description] intValue]] forKey:@"point"];maybe help you ^____^

mr.octobor 2010-08-25 14:12:19

Answer 2

+1 A:

There are three solutions:

Put NSNumber instances into the dictionaries in place of the strings (e.g., @"100") you currently have. NSNumber objects should compare themselves numerically.
Send the array a sortUsingComparator: or sortUsingFunction:context: message instead of sortUsingDescriptors:, passing a block or function that retrieves the strings and compares them numerically (by sending them compare:options: messages with the NSNumericSearch option).

Note that the block or function will be passed the whole dictionaries, not the strings, since it has no way to know which strings to extract, so you'll have to get the strings out of the dictionaries yourself in order to compare them.
Replace the dictionaries with model objects that have properties in place of the dictionary keys. If you declare the property with a numeric type (e.g., NSUInteger), then when the array uses KVC to access the property, it will get NSNumber objects, which, as noted under #1 above, should compare themselves numerically.

I would go with #3.

Peter Hosey 2010-08-24 19:52:49

how to declare the property with a numeric type ?

mr.octobor 2010-08-25 13:27:34

Give it a numeric type when you declare it. The documentation I linked to shows you how to declare a property.

Peter Hosey 2010-08-25 13:38:29

very thank I use choice and it work!. this is my code for everyone[item setObject:[NSNumber numberWithInt:[[[_modeObject valueForKey:@"point"] description] intValue]] forKey:@"point"];**item is NSMutableArray

mr.octobor 2010-08-25 14:11:06

I use choice #3

mr.octobor 2010-08-25 14:11:27

mr.october: That's not #3, that's #1, and implemented in a very roundabout way. Isn't this code going to cause problems later on when other code expects to find strings there and gets numbers instead? Why not just create numbers and put them into the dictionary in the first place? And why not actually do #3 (replace your dictionaries with model objects)?

Peter Hosey 2010-08-25 14:18:07

I must read data from core data and put them in to NSMutableArray.I'm newbie in Xcode and very thank for your help because I looking for this solution more then 3 days.very thanks ^__^

mr.octobor 2010-08-26 09:00:27

mr.octobor: You don't “read data from Core Data”; Core Data gives you managed objects, which are the model objects you should be using. You should set the `point` attribute of your high-score entity to be of the Integer 32 type, not a string. Then, just make a mutable copy of the array of score objects, and sort that by the `point` key using NSSortDescriptor. You should not create dictionaries for this at all.

Peter Hosey 2010-08-26 09:10:01

oh! really I don't know it before.first my code is[item setObject:[[_modeObject valueForKey:@"name"] description] forKey:@"name"];[item setObject:[[_modeObject valueForKey:@"point"] description] forKey:@"point"];[hightScore addObject:[item copy]];but after I have your suggestion I try and it OK.[item setObject:[[_modeObject valueForKey:@"name"] description] forKey:@"name"];[item setObject:[NSNumber numberWithInt:[[[_modeObject valueForKey:@"point"] description] intValue]] forKey:@"point"];[hightScore addObject:[item copy]];*item > NSMutableDictionary*hightScore > NSMutableArray

mr.octobor 2010-08-27 11:59:50

No, that's not it. There is no need to create the `item` dictionary at all. (Also, you're leaking it when you put it into the array, as you're not releasing it.) Just put the model objects into the array and sort it.

Peter Hosey 2010-08-27 12:31:03

Yes I try to put it into array but I don't know how to get data from that array !?

mr.octobor 2010-08-29 02:22:11

The same way you get the dictionaries out. If you want a more specific answer, you should ask a more specific (and separate) question.

Peter Hosey 2010-08-29 09:27:02

OK Thanks ^_____^

mr.octobor 2010-08-30 02:48:07

Answer 3

A:

how to declare the property with a numeric type ?

mr.octobor 2010-08-25 13:41:08

See the documentation I linked to in my answer.

Peter Hosey 2010-08-25 13:55:56

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Sort NSMutableArray

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