error with jquery. validate.js

Question

Hi, I use this great jquery script but I recieve an error with debug mode "----This is a debug mode, you got a problem with your form, it will try to help you, refresh when you think you nailed down the problem you are not going into the success fonction and jsonValidateReturn return nothing-----" or display this inside firefox errors console: Error: data.jsonValidateReturn is undefined Source file: js/jquery.validationEngine.js When I check an available username all is ok and it validates correctly all fields ... ajaxsubmitregister.php controls all

require_once("../config/config.php");
$arrayToJs = array();
$arrayToJs[0] = $validateId;
$arrayToJs[1] = $validateError;
$isValidate = true;  

if($isValidate == true)
{
    echo "true";
}
else
{ 
    $isValidate = false;

    if (!function_exists('json_encode'))
    {
        function json_encode($a=false)
        {
            if (is_null($a)) return 'null';
            if ($a === false) return 'false';
            if ($a === true) return 'true';
            if (is_scalar($a))
            {
            if (is_float($a))
            {
                // Always use "." for floats.
                return floatval(str_replace(",", ".", strval($a)));
            }

            if (is_string($a))
            {
                static $jsonReplaces = array(array("\\", "/", "\n", "\t", "\r", "\b", "\f", '"'), array('\\\\', '\\/', '\\n', '\\t', '\\r', '\\b', '\\f', '\"'));
                return '"' . str_replace($jsonReplaces[0], $jsonReplaces[1], $a) . '"';
            }
            else
                return $a;
        }

        $isList = true;

        for ($i = 0, reset($a); $i < count($a); $i++, next($a))
        {
            if (key($a) !== $i)
            {
                $isList = false;
                break;
            }
        }

        $result = array();

        if ($isList)
        {
            foreach ($a as $v) $result[] = json_encode($v);
            return '[' . join(',', $result) . ']';
        }
        else
        {
            foreach ($a as $k => $v) $result[] = json_encode($k).':'.json_encode($v);
            return '{' . join(',', $result) . '}';
        }
    }
}

echo'{"jsonValidateReturn":'.json_encode($arrayToJs).'}';

}