how to printf a loop result?

Question

How to printf results from a loop?

For example if i have this something simple like this:

k[0]=2;
k[1]=3;
k[2]=4;

for (i = 0 ; i <= 2 ; i++)
{
    x[i]=5*k[i];
}

How do I print out the results for x[0],x[1],x[2] without having to keep repeating the array in printf? As in

printf("%d %d %d\n",x[0],x[1],x[2]);

I dont really want to do the printf above because for my problem i actally have an array of 100 values, i cant be repeating the x[0],x[1]... for one hundred times.

Hope someone can help out thanks loads!

Answer 1

Maybe this:

for (j = 0; j < 100; j++) {
    printf ("%d ",x[j]);
}
printf ("\n");

Answer 2

You can put a printf in a loop. If you don't put a "\n" in the printf, the next printf will be on the same line. Then when you are done with the loop, printf just a newline.

There is no printf type specifier for an array, you have to loop through the array elements and print them one by one.

Answer 3

You can think of doing it this way:

k[0]=2;
k[1]=3;
k[2]=4;

for (i = 0 ; i <= 2 ; i++)
{
    x[i]=5*k[i];
    printf("%d",x[i]);
}
printf("\n");

Answer 4

Why can't you print them out as you go around the loop?

for (i = 0 ; i <= 2 ; i++)
{
    x[i]=5*k[i];
    printf("%d ", x[i]);
}
printf("\n");

Other than that you could have another loop underneath which strcats the results together into a single string for output.

Answer 5

You should place the printf statement in the loop:

k[0]=2; 
k[1]=3; 
k[2]=4; 

for (i = 0 ; i <= 2 ; i++) 
{ 
    x[i]=5*k[i]; 
    printf("%d ", x[i]);
} 

printf("\n");

Answer 6

#include <stdio.h>
#define FOR_PRINT(index, array, size, format) \
    { \
        for(index = 0; index < size; ++index){ \
            printf(format, array[index]); \
        } \
        printf("\n");
    } \

int main(){
    int array [] = {1,2,3};
    int i;
    FOR_PRINT(i, array, 3, "%d ");
    return (0);
}

You can always use an MACRO for that.

My previous example is not the safest, or the most readable example of a macro, but can be a starting point for you.

Answer 7

You have stored 100 numbers in an array and want to display the same.

In simple language, we can say an array is collection of items of similar types.

For this, you have to first declare the array size, suppose you have declared an array as x[100], then it will store 100 numbers, with index number 0 to 99 or you can do the same by declaring each variable like x[0]=20,x[1]=30 .......x[99]=98, but this will be more time consuming.So its better if you do as follows.

Accept values

int x[100];    
 int index;
 for(index=0;index<100;index++)
 {
        printf("\nEnter %d number:",index+1);
        scanf("%d",x[i]);
  }

Display

for(index=0;index<100;index++)

{

printf("\nArray element at index %d is %d",index,x[i];

}

This will be help you.