Xml Traversing with javascript

Question

<links>
    <osname name="windows xp" links="xyz" />
    <osname name="windows 2k" links="xyz" />
</links>
<owners name="microsoft">
    <os name="windows xp" />
    <os name="windows 2k" />
    <os name="windows 2003" />
    <os name="windows 7" />
</owners>
<owners name="microsoft">
    <os name="windows xp" />
    <os name="windows 95" />
    <os name="windows 98" />
    <os name="windows vista" />
</owners>

Javascript

it should take the links from links->osname and match it with the owners->os =>name

and os name is suppose to be once only, it should not repeat later on.

Thanks in advance

Answer 1

Assuming the above is store in variable txt:

if (window.DOMParser) {
  parser=new DOMParser();
  xmlDoc=parser.parseFromString(txt,"text/xml");
} else {
  xmlDoc=new ActiveXObject("Microsoft.XMLDOM");
  xmlDoc.async="false";
  xmlDoc.loadXML(txt); 
}

And then to access the XML you provided in javascript:

// links.osname[0].attribute(name)
xmlDoc.childNodes[0].childNodes[0].getAttribute('name');
// outputs: windows xp

// owners.os[2].attribute(name)
xmlDoc.childNodes[1].childNodes[2].getAttribute('name');
// outputs: windows 2003

There's quite a lot of code out on the nets explaining all this (see also: getNamedItem, getElementsByTagName, nodeValue ... and lots more)

To traverse:

for(i=0;i<xmlDoc.childeNodes[1].childNodes.length;i++) {
  //Access each node in the set:
  xmlDoc.childNodes[1].childNodes[i]
}

Answer 2

This stylesheet:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt;
    <xsl:output omit-xml-declaration="yes"/>
    <xsl:key name="kOwnersByName" match="owners" use="@name"/>
    <xsl:key name="kOsByOwnerAndName" match="os" 
             use="concat(../@name,'+++',@name)"/>
    <xsl:template match="node()|@*">
        <xsl:copy>
            <xsl:apply-templates select="node()|@*"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="owners"/>
    <xsl:template match="owners[count(.|key('kOwnersByName',@name)[1])=1]">
        <xsl:variable name="vOwner" select="@name"/>
        <xsl:copy>
            <xsl:apply-templates select="@*"/>
            <xsl:for-each select="../links/osname/@name">
                <xsl:apply-templates 
                 select="key('kOsByOwnerAndName',concat($vOwner,'+++',.))[1]"/>
            </xsl:for-each>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

With proper input:

<root>
    <links>
        <osname name="windows xp" links="xyz" />
        <osname name="windows 2k" links="xyz" />
    </links>
    <owners name="microsoft">
        <os name="windows xp" />
        <os name="windows 2k" />
        <os name="windows 2003" />
        <os name="windows 7" />
    </owners>
    <owners name="microsoft">
        <os name="windows xp" />
        <os name="windows 95" />
        <os name="windows 98" />
        <os name="windows vista" />
    </owners>
</root>

Output what I think is what you want:

<root>
    <links>
        <osname name="windows xp" links="xyz"></osname>
        <osname name="windows 2k" links="xyz"></osname>
    </links>
    <owners name="microsoft">
        <os name="windows xp"></os>
        <os name="windows 2k"></os>
    </owners>
</root>

Answer 3

More convenient way of working with xml, is to use jQuery.

Just retrieve the data:

$.ajax({ url: '/Document.xml', success: ProcessData, contentType: 'text/xml' });

and do whatever you want:

function ProcessData(data) {
    var xml = $(data);
    xml.find("links osname[name]").each(function () { 
        var value = $(this).attr("links")); 
        // etc.
    });
}

If you know jQuery, it should be easy task for you.