How can I get an ListView item from the (X,Y) position?

Question

I am dropping something in a ListView in WPF. I need to know the item in the (X,Y) position I am dropping. How can I do this?

Answer 1

You want to use the GetItemAt function. You may also need to call the PointToClient function before the GetItemAt since you need to work with client coordinates.

Answer 2

The WPF ListView doesn't have GetItemAt. I return to my original problem.

Answer 3

Done! Thanks to this article http://www.codeproject.com/KB/WPF/WPF_Drag_And_Drop_Sample.aspx

private int GetCurrentIndex(GetPositionDelegate getPosition)
{
    int index = -1;
    for (int i = 0; i < clasesListView.Items.Count; ++i)
    {
        ListViewItem item = GetListViewItem(i);
        if (this.IsMouseOverTarget(item, getPosition))
        {
            index = i;
            break;
        }
    }
    return index;
}

private bool IsMouseOverTarget(Visual target, GetPositionDelegate getPosition)
{
    Rect bounds = VisualTreeHelper.GetDescendantBounds(target);
    Point mousePos = getPosition((IInputElement)target);
    return bounds.Contains(mousePos);
}

delegate Point GetPositionDelegate(IInputElement element);

ListViewItem GetListViewItem(int index)
{
    if (clasesListView.ItemContainerGenerator.Status != GeneratorStatus.ContainersGenerated)
        return null;

    return clasesListView.ItemContainerGenerator.ContainerFromIndex(index) as ListViewItem;
}

Answer 4

Hoops, sorry. This should work fine:

FrameworkElement element = (FrameworkElement)e.OriginalSource;

ListViewItem lvi = (ListViewItem)listView1.ItemContainerGenerator.ContainerFromItem(fe.DataContext);