the code
public partial class Table_Traversing : System.Web.UI.Page
{
Table table1 = new Table();
Button button1 = new Button();
protected void Page_Load(object sender, EventArgs e)
{
for (int adding_rows = 0; adding_rows < 4; adding_rows++)
{
TableRow table_row1 = new TableRow();
TableCell table_cell1 = new TableCell();
TableCell table_cell2 = new TableCell();
Label The_text = new Label();
CheckBox checkmate = new CheckBox();
The_text.Text = "This is the text :-)";
checkmate.ID = "checkmate";
table_cell2.Controls.Add(checkmate);
table_cell1.Controls.Add(The_text);
table_row1.Controls.AddAt(0, table_cell1);
table_row1.Controls.AddAt(1, table_cell2);
table1.Rows.Add(table_row1);
}
button1.Text = "click me to export the value";
form1.Controls.AddAt(0, table1);
form1.Controls.AddAt(1, button1);
button1.Click += new EventHandler(button1_Click);
}
void button1_Click(object sender, EventArgs e)
{
CheckBox check_or_not = new CheckBox();
for (int i = 0; i < table1.Rows.Count; i++)
{
check_or_not = (CheckBox)table1.Rows[i].FindControl("checkmate");
Response.Write(check_or_not.Checked.ToString());
}
}
}
the error
Multiple controls with the same ID 'checkmate' were found. FindControl requires that controls have unique IDs.
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.
Exception Details: System.Web.HttpException: Multiple controls with the same ID 'checkmate' were found. FindControl requires that controls have unique IDs.