Regular expression how to search for () and replace with[]

Question

Silly question, but I do not know how to find (2000) into a regular expression and replace it with [2000]

Answer 1

Like this: yourString.replace(/\(2000\)/, "[2000]");

Answer 2

You can do:

str.replace(/\((\d+)\)/g, "[$1]");

Regex used: \((\d+)\)

• ( and ) are special char in regex used for grouping, to match literal ( ), you need to escape them as \( \)
• \d is short for a digit. \d+ means one or more digits.
• ( ) is to group and remember the number. The remembered number will later be used in replacement.
• g for global replacement. Mean every occurrence of the patten in the string will be replaced.
• $1 is the number between ( )that was grouped and remembered.
• / / are the regex delimiters.

Answer 3

function _foo(str) {
   return str.replace(/[(](\d*)[)]/, '[$1]');
}

alert( _foo("(2000)") );  // -> '[2000]'
alert( _foo("(30)") );    // -> '[30]'
alert( _foo("(abc)") );   // -> '(abc)'
alert( _foo("()") );      // -> '[]'

Answer 4

Try this:

function foo(S) { 
    return S.replace(/\(([^\)]+)\)/g,"[$1]");
}