suppose you have the following form :
<form id="ajax-form">
<fieldset>
<input type="text" id="firstname" name="firstname" />
<input type="text" id="lastname" name="lastname" />
<input type="submit" value="send" />
</fieldset>
</form>
using jQuery
$(document).ready(function(){
$("#ajax-form").submit(function(){
$.ajax({
type: "POST",
url: "Person/Add",
data: $("#ajax-form").serialize(),
success: function (response) {
// whatever you want to happen on success
},
error: function (response) {
alert('There was an error.');
}
});
});
});
Accessing Your Data in the Action Method.
public ActionResult Add(FormCollection form)
{
string firstname = form["firstname"];
string firstname = form["lastname"];
// do whatever you want here
// then return something to the view
return Json(/*some object*/);
}
another way is to use Microsoft Ajax
<% using (Ajax.BeginForm("Add", "Person",
new AjaxOptions() {
UpdateTargetId = "formDiv",
InsertionMode = InsertionMode.Replace,
HttpMethod = "Post" })) {%>
<fieldset>
// Form Elements Here.
</fieldset>
<% } %>
UpdateTargetId
is the id of the html element to be targeted.
The InsertionMode option has three values Replace
, InsertAfter
, InsertBefore
Hope that was helpful
Update : you don't have to return a Json result in your action method you can simply return a partial view or any HTML code as the response object and then insert it using jQuery.