I've been trying to use XSL with Google Chrome, but with no success.
I read that Chrome have some bugs with XSLT, and one of them is that it doesn't support xsl:include. Bug can be checked here: http://code.google.com/p/chromium/issues/detail?id=8441.
After some research I found a new version of the transform plugin by Daer System, and it makes xsl:include work at Chrome.
Heres the plugin page:
plugins.jquery.com/project/Transform
Now my problem is:
I use a default include in some xsl templates, and this include uses a parameter that is passed to the top level one.
So its like i have the top.xsl template that declares a [xsl:param name="param" /], and i use this param with the included.xsl, that is called by the 1st one with [xsl:include href="included.xsl"] . This works both on Firefox and Internet Explorer, but not on Chrome. I saw a question here on stackoverflow where some guy re-write the webkit fix function from the plugin, but it doesn't work with xsl:param this way.
Does anyone know some way to use [xsl:param] like this in Google Chrome?