PHP: How to make a list of film and genre (example) - MySQL Join Many-to-Many (want?) and the PHP?

Answer 1

Do a many-to-many sql query:

SELECT m.movie_id, m.movie_title, g.genre_id, g.genre_title
FROM movies m 
INNER JOIN movie_genres mg ON m.movie_id = mg.movie_id
INNER JOIN genres g ON g.genre_id = mg.genre_id

Then loop through the result and group by movie id.

Answer 2

SELECT
    T1.movie_id,
    T1.movie_title,
    T2.genre_id,
    T2.genre_title
FROM
    Table3 AS T3
    INNER JOIN Table1 AS T1 ON T3.movie_id = T1.movie_id
    INNER JOIN Table2 AS T2 ON T3.genre_1 = T2.genre_id
ORDER BY
    T1.movie_id

That would return something like this:

movie_id | movie_title   | genre_id | genre_title
1        | title_movie_1 | 1        | title_genre_1
1        | title_movie_1 | 2        | title_genre_2
2        | title_movie_2 | 1        | title_genre_1
2        | title_movie_2 | 3        | title_genre_3
3        | title_movie_3 | 1        | title_genre_1
3        | title_movie_3 | 3        | title_genre_3
3        | title_movie_3 | 2        | title_genre_2

Afterwards, you can just loop through all the records; print movie_title if movie_id changed, then print genre_title.

$currentMovie = 0;
while ($row = mysql_fetch_row($result))
{
    if($row['movie_id'] != $current_movie)
    {
        $currentMovie = $row['movie_id'];
        echo "Movie: <a href=\"movie/" + $row['movie_id'] + "\">" + $row['movie_title'] + "</a><br />Genre:<br />"
    }
    echo "<a href=\"genre/" + $row['genre_id'] + "\">" + $row['genre_id'] + "</a><br />"
}