Sorting MYSQL Tag table

Question

Hi there,

just wondering if it is possible to get the top 10 COUNT results and ordering by COUNT and alphabetically?

I have the following tables,

tags
-------
id | title

.

tagged
------
tag_id | post_id

And the following SQL query

SELECT tag.*, COUNT(td.tag_ID) AS tagcount
FROM Tagged td
LEFT JOIN Tags tag ON td.tag_ID = tag.tag_ID
GROUP BY td.tag_ID
ORDER BY tagcount DESC, tag.tag_Title ASC

Any ideas?

Thanks in advance

---

Edit

Sorry if I didnt explain it properly.

The query works and I didnt add LIMIT 10 due to wanting to see the entire result set first.

The query I have works, however at the following example result

tag_ID  tag_Title  tagcount
1          Science  3
3          Chemistry 2
4          Misc      1
5          Maths       1
2          Sport       1

I would want Chemistry to come above Science though.

i.e. top ten highest counts.. sorted alphabetically

---

Result

Thanks to you both.. Daniel and Sled.

Here is a working example

( 
   SELECT     t.*, COUNT(*) AS tagcount
   FROM       tagged td
   LEFT JOIN  tags t ON (t.id = td.tag_id)
   GROUP BY   td.tag_id
   ORDER BY   tagcount DESC, t.title ASC
   LIMIT      3
) ORDER BY title ASC;

Answer 1

Does the query work? If yes, you could use LIMIT 0, 10 to get only the top 10 rows.

SELECT tag.*, COUNT(td.tag_ID) AS tagcount
FROM Tagged td
LEFT JOIN gen_Tags tag ON td.tag_ID = tag.tag_ID
GROUP BY td.tag_ID
ORDER BY tagcount DESC, tag.tag_Title ASC LIMIT 0, 10

Another thing you might be interested in, is ranking. See here: http://www.fromdual.com/ranking-mysql-results

Edit

Maybe a subquery does what you want:

SELECT list.* FROM (
  SELECT tag.*, COUNT(td.tag_ID) AS tagcount, 
  FROM Tagged td
  LEFT JOIN gen_Tags tag ON td.tag_ID = tag.tag_ID
  GROUP BY td.tag_ID
  ORDER BY tagcount DESC LIMIT 0, 10
) AS list ORDER BY list.tag_Title ASC, list.tagcount DESC

Answer 2

UPDATE:

Further to the new comment below:

( 
   SELECT     t.*, COUNT(*) AS tagcount
   FROM       tagged td
   LEFT JOIN  tags t ON (t.id = td.tag_id)
   GROUP BY   td.tag_id
   ORDER BY   tagcount DESC, t.title ASC
   LIMIT      3
) ORDER BY title ASC;

Result:

+------+------------+----------+
| id   | title      | tagcount |
+------+------------+----------+
|    3 | javascript |        2 |
|    1 | mysql      |        2 |
|    2 | php        |        3 |
+------+------------+----------+
3 rows in set (0.00 sec)

Simply change the LIMIT 3 to LIMIT 10 to get the top 10 instead of the top 3.

---

Previous Answer:

Why don't you add a LIMIT 10 to your query?

SELECT     t.*, COUNT(*) AS tagcount
FROM       tagged td
LEFT JOIN  tags t ON (t.id = td.tag_id)
GROUP BY   td.tag_id
ORDER BY   tagcount DESC, t.title ASC
LIMIT      10;

Test case:

CREATE TABLE tags (id int, title varchar(20));
CREATE TABLE tagged (tag_id int, post_id int);

INSERT INTO tags VALUES (1, 'mysql');
INSERT INTO tags VALUES (2, 'php');
INSERT INTO tags VALUES (3, 'javascript');
INSERT INTO tags VALUES (4, 'c');

INSERT INTO tagged VALUES (1, 1);
INSERT INTO tagged VALUES (2, 1);
INSERT INTO tagged VALUES (1, 2);
INSERT INTO tagged VALUES (2, 2);
INSERT INTO tagged VALUES (3, 3);
INSERT INTO tagged VALUES (2, 4);
INSERT INTO tagged VALUES (3, 4);
INSERT INTO tagged VALUES (4, 5);

Result (using LIMIT 3):

+------+------------+----------+
| id   | title      | tagcount |
+------+------------+----------+
|    2 | php        |        3 |
|    3 | javascript |        2 |
|    1 | mysql      |        2 |
+------+------------+----------+
3 rows in set (0.00 sec)

Note how the [c] tag fell out of the top 3 results, and rows are ordered alphabetically in case of a tie.