C function to escape string for shell command argument?

Question

What function should I use to escape strings for shell command argument in C?

1. I have a string:

   This is a string with () characters

2. This will be error:

   echo This is a string with () characters

3. These are OK:

   echo "This is a string with () characters"

   echo This is a string with \(\) characters

Is there a predefined function convert #2 to #3 in C?

Answer 1

Nothing pre-defined, and which characters need escaping depends on your shell. Look at the docs for your shell, and replace each X with \X. Using double quotes " will require the same treatment if the string you're enclosing contains a ".

Also note that this will get more complicated if you intend to encapsulate more complicated expressions (anything compounded with a ';', for example)

Answer 2

Your second version of 3. is easy, no?

printf("\"%s\"", your string);

Answer 3

There is no predefined function.

However, I believe it's sufficient to just enclose any shell argument in single quotes, and making sure that single quotes are escaped.

That's the logic of the escapeshellarg function in PHP and I believe it works reasonably well.

Answer 4

Replacing all instances of ' with '\'' then enclosing the whole string in single quotes (') is one safe way. This works even with embedded newlines. Another method would be to insert \ before each character, except that then you have to do some special treatment for newlines since \ followed by a newline is ignored by the shell, not treated as a literal newline. You'd have to surround newlines with ' (single quotes).