Hi,
I want to implement .draggable class to all elements in my document, with an existing id using jQuery 1.4.2
<div id="blabla">asdsda</div> -> OK
<div>dsds</div> -> NOT OK
Is this possible ?
i tried : $("*[id!=null]") but i does not work :s
views:
60answers:
3
+1
A:
$("*[id]")
should work, and - for the record -
$("*:not([id])")
is the opposite.
Tomalak
2010-09-10 13:44:10
works great, thanks !
div1n
2010-09-10 13:49:59
+1 But I think I'd probably limit the query to descendants of `body` just to make it a little quicker. `$('body [id]')`
patrick dw
2010-09-10 13:52:45
@patrick: Marginally, if at all.
Tomalak
2010-09-10 14:44:42
Marginally, yes. If at all? Well, if there's one additional tag, (HTML for example) then of course there must be *some* difference, though marginal. Also, what if a tag in the HEAD has an ID? Maybe calling `.draggable()` on a `<script>` tag is innocuous... but then maybe not.
patrick dw
2010-09-10 15:20:32
@patrick: From a "time to execute" perspective, I do not expect any difference that's more than academic. From a "be specific to avoid bugs" perspective, your's may be the better choice, however.
Tomalak
2010-09-10 15:30:25
Fair enough. :o) I certainly don't disagree with your assessment of the performance difference. Such is the case of many performance-related 'best practices' we may do.
patrick dw
2010-09-10 15:40:25
A:
$('[id]')
This will grab all elements that have an 'id' attribute.
Or to get all divs with an 'id' attribute you can do:
$('div[id]')
Rocket
2010-09-10 13:51:34