I don't quite understand the \ and \.. syntax in the compile error I'm getting
Error 6 The command " copy c:\project\new\.. \new\bin\x64\debug\garmin.dll c:\project\new\bin\x64\Debug\ " exited with a code 1.
Can anyone explain this to me?
views:
30answers:
2
A:
It's the same as from the command line. .. is on directory "up".
BioBuckyBall
2010-09-10 21:01:55
A:
\..\ simply means "the parent directory". So in this case, \new\..\new\ contains redundancy, and simply means \new\. You are trying to copy a file to the directory it is already in, but it won't happen because the file already exists (and perhaps is in use?)
Mark H
2010-09-10 21:05:23