ansaurus

Question

how he give me 0?

Answer 1

+1 A:

var i;
if (ID.indexOf(",") != -1)
    i = ID.split(',');
else
    i = ID;

teukkam 2010-09-11 12:17:15

This should work assuming ID always contains either a comma separated list of integer or a lone integer without a comma.

teukkam 2010-09-11 12:19:29

Except if ID is a **number** and not a string, then the call to `.search()` will fail.

Pointy 2010-09-11 12:26:28

Well you're right, it's also assuming it's a string.

teukkam 2010-09-11 14:05:43

Answer 2

A:

Exactly like what you posted except you check for the presence of the seperator with JavaScripts .indexOf() string method.

ikanobori 2010-09-11 12:18:01

Won't work when the variable "ID" is set to a number instead of a string.

Pointy 2010-09-11 12:28:45

Answer 3

A:

String.prototype.mySplit = function(sep) {
    return (this.indexOf(sep) != -1) ? this.split(sep) : [this];
};

Example:

//var ID= '12,32,23,78';
var ID= '12';

//Update
if (typeof(ID)=='number') ID += '';

var i = ID.mySplit(',');

alert(i[0]);

Otar 2010-09-11 12:24:05

Won't work at all if ID is a number and not a string.

Pointy 2010-09-11 12:27:24

This is completely unnecessary. `"12".split(",")` will return `[ "12" ]` - you don't need to write a separate function to get this behavior.

Andy E 2010-09-11 12:37:27

You didn't mentioned that ID could be an integer, see updated code.

Otar 2010-09-11 12:37:56

Answer 4

+5 A:

Pointy 2010-09-11 12:25:35

+1. Although the OP wasn't clear enough in his question, the other answers seem to be misunderstanding the inner workings of the *split()* method - if the separator character isn't in the string, *split()* will still work in exactly the same way - returning an array with only one element in it.

Andy E 2010-09-11 12:35:38

Yes, I realize it was pretty vague, and indeed I don't know what he means when he says "he give me 0" of course, but it's almost certainly what the problem is.

Pointy 2010-09-11 12:37:17

@Andy E: yup, though at least I found it suspicious that the split method was giving him 0, until Pointy clarified it was a data type thing. +1

BoltClock 2010-09-11 12:39:46

Answer 5

A:

    var ID= "12,32,23,78";

    var i = ID.split(',');

    will return [12,32,23,78]

    var ID= "12";

    var i = ID.split(',');

    will return [12] -- this is also an array

however you may do this

    var ID= "12";

    var i = ID.split(',') || ID;

Praveen Prasad 2010-09-11 12:34:57

ansaurus

tags:

views:

answers:

how he give me 0?

related questions