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Question

Answer 1

A:

\w+\s+[a-zA-Z-]+

GameBit 2010-09-13 17:13:48

hi gamebit - thanks for the response. i'm using ascii and when I enter that - doesnt like \w and \s - gives me "unrecognized escape sequence"

Tom 2010-09-13 17:15:03

Answer 2

+1 A:

You can use /([\p{L}'-]+) ([\p{L}'-]+)/ to catch all possible letter. Or /([a-z'-]+) ([a-z'-]+)/i to catch only ascii letters.

The group ([\p{L}'-]+) means [\p{L}'-] repeated at least one time. And \p{L} means any unicode letter. The - at the end means that "-" is allowed in names.

Note : When you capture characters with [] the hyphen must be either at the start of your characters set or at the end.

Edit :

Mr. O'Brien is happy now.

Resources :

Colin Hebert 2010-09-13 17:15:13

+1 for covering Unicode.

Daniel Vandersluis 2010-09-13 17:16:01

thanks colin. yeah im using C# - doesnt like \w and \s - gives me "unrecognized escape sequence"

Tom 2010-09-13 17:19:58

@Tom remember to escape the \ either by writing "\\s" or @"\s"

Arkain 2010-09-13 17:28:52

It's not C# Tom - it's you. You must escape your backslashes or prefix the string with @ ie: string pattern = @"\w";

Goran 2010-09-13 17:33:22

yep sorry - forgot - been a while :) thx

Tom 2010-09-13 17:34:03

In this code you can't really detect "René Hadron van der Ööps" because you don't really know what is his firstname or lastname, plus I didn't use the \s, I suggest you to use it for the lastname.

Colin Hebert 2010-09-13 17:36:30

err i seem to be getting a bug with the space ? i.e. seems even it i enter "tom jones" - still gives me my errore text "space is required"

Tom 2010-09-13 17:54:33

What regex did you use ? It worked for me with `@"([\p{L}'-]+) ([\p{L}'-]+)"` on http://derekslager.com/blog/posts/2007/09/a-better-dotnet-regular-expression-tester.ashx

Colin Hebert 2010-09-13 17:55:54

cool sorry yeah - dodgy regex tester :)

Tom 2010-09-13 18:14:09

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