Mysql: Select where count of one field is greater than one.

Question

I want to do something like:

SELECT * 
  FROM db.table 
 WHERE COUNT(someField) > 1

how do I do this in MySql.

Answer 1

Use the HAVING, not WHERE clause, for aggregate result comparison.

Taking the query at face value:

SELECT * 
  FROM db.table 
HAVING COUNT(someField) > 1

Ideally, there should be a GROUP BY defined for proper valuation in the HAVING clause, but MySQL does allow hidden columns from the GROUP BY...

Is this in preparation for a unique constraint on someField? Looks like it should be...

Answer 2

One way

SELECT t1.* 
FROM db.table t1
WHERE exists 
      (SELECT *
      FROM db.table t2 
      where t1.pk != t2.pk 
      and t1.someField = t2.someField)

Answer 3

As OMG Ponies stated, the having clause is what you are after. However, if you were hoping that you would get discrete rows instead of a summary (the "having" creates a summary) - it cannot be done in a single statement. You must use two statements in that case.

Answer 4

You can also do this with a self-join:

SELECT t1.* FROM db.table t1
JOIN db.table t2 ON t1.someField = t2.someField AND t1.pk != t2.pk