Strange behavior when applying Array.prototype.slice method to result of querySelectorAll

Question

I'am trying to use jquery's selectors as custom Selenium locate strategy. Exactly as in this article http://johnjianfang.blogspot.com/2009/04/how-to-use-jquery-to-create-custom.html

Unfortunatly when I use selenium.click('jquery=a.mylink') method nothing happens.

But selenium.click('css=a.mylink') still works perfectly.

I did a little research and found that problem is in how jquery convers result of querySelectorAll. Here is the snippet from jquery 1.4.2:

Sizzle = function(query, context, extra, seed){
    context = context || document;

    // Only use querySelectorAll on non-XML documents
    // (ID selectors don't work in non-HTML documents)
    if ( !seed && context.nodeType === 9 && !isXML(context) ) {
        try {
            return makeArray( context.querySelectorAll(query), extra );
        } catch(e){}
    }

    return oldSizzle(query, context, extra, seed);
};


var makeArray = function(array, results) {
    array = Array.prototype.slice.call( array, 0 );

    if ( results ) {
        results.push.apply( results, array );
        return results;
    }

    return array;
};

When I change makeArray like this:

var makeArray = function(arrayLikeObject, results) {

    var array = new Array(arrayLikeObject.length);
    for (var i = 0, n = arrayLikeObject.length; i < n; i++) {
        array[i] = arrayLikeObject[i];
    }

    if ( results ) {
        results.push.apply( results, array );
        return results;
    }

    return array;
};

It solves this strange problem.

Any ideas why this fix works??!