Changing Individual Characters of a Character Array in C

Question

Possible Duplicate:
Why does this Seg Fault?

Hello, I have a

char* str = "blah";

And I now want to change one of the characters to something else, say a number 3. I am trying to do so with:

str[2] = '3';

However I am getting a seg fault at this line of code. Any idea why?

Answer 1

This is a duplicate question. See here.

Answer 2

That's not an array of chars. It's a pointer to char initialized with a string constant. String constants cannot be modified, but if you make it an array of chars rather than a char pointer, it will work. e.g.

char str[] = "blah";
str[2] = '3';