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What does the jquery selector '$("#someID > * *")' mean?

Answer 1

+8 A:

It selects all grandchildren or lower of #someID.

Explanation:

#someID > * selects all direct children of #someID.
Adding * will select all descendants of those children. (but not the children themselves)

Thus, it will select all descendants of #someID except for its direct children.

It could also be written as $('#someID *').not('#someID > *').

SLaks 2010-09-20 17:53:14

Proof: http://jsfiddle.net/wh9W9/1/

Harmen 2010-09-20 18:01:26

Could also be written as: `$('#someID').children().find('*');`

patrick dw 2010-09-20 18:08:56

@Patrick: You're right; that's much clearer, and probably a little faster.

SLaks 2010-09-20 18:12:02

Answer 2

+2 A:

$('#someID > * *')

Get all/any elements which are direct/immediate children of #someID and then get any descendants inside those elements there by only getting descendants.

Sarfraz 2010-09-20 17:54:29

Nope. It won't select its direct children.

Harmen 2010-09-20 17:57:25

@Harmen: I did not say either, it will select descendants ultimately :)

Sarfraz 2010-09-20 17:59:03

@Sarfraz, you used the word `get` two times with another meaning, I guess...

Harmen 2010-09-20 18:04:35

@Harmen: Yes that could have caused the confusion, added few more words at the end. Thanks :)

Sarfraz 2010-09-20 18:10:51

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What does the jquery selector '$("#someID > * *")' mean?

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