Are you able to use COUNT in a query with a HAVING clause so that the COUNT returns the number of rows? When I try, Im getting the count of the number of times the ID shows up in the table. Here is the query:
SELECT col_appid, min(col_payment_issued_date) as PayDate
FROM tbl_ui_paymentstubs
WHERE isnull(col_payment_amount,0) > 0
GROUP BY col_appid
HAVING min(col_payment_issued_date) >= '09/01/2010' and min(col_payment_issued_date) <= '09/30/2010'
I get back 6 rows, which is fine, but i'd like to just get back the number 6.
I found I could do it this way, but was wondering if there was another, more elegant way:
WITH Claims_CTE(AppID, PayDate) as
(
SELECT col_appid, min(col_payment_issued_date) as PayDate
FROM tbl_ui_paymentstubs
WHERE isnull(col_payment_amount,0) > 0
GROUP BY col_appid
HAVING min(col_payment_issued_date) >= '09/01/2010' and min(col_payment_issued_date) <= '09/30/2010'
)
SELECT count(AppID) as Amount from Claims_CTE
`