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74

answers:

4
30 days hath September,
   April, June and November,
 All the rest have 31,
   Excepting February alone
(And that has 28 days clear,
   With 29 in each leap year).

Can I obtain this info anagrammatically? (I don't mean the poem, of course)

Thanks!
Manuel

A: 
int datsOfMonth(DateTime dt) {
    switch(dt.getMonthOfYear()) {
        case 1: return 31;
        case 2: return isLeap(dt.year()) ? 29 : 28; // you'll have to do isleap on your own, but it's easy, and probably included somewhere
        case 3: return 31;
        case 4: return 30;
        case 5: return 31;
        case 6: return 30;
        case 7: return 31;
        case 8: return 31;
        case 9: return 30;
        case 10: return 31;
        case 11: return 30;
        case 12: return 31;
    }
    throw new IllegalArgumentException();
}
glowcoder
A: 
Calendar cal = Calendar.getInstance();
cal.set(Calendar.MONTH, yourMonth);
cal.set(Calendar.YEAR, yourYear);
cal.getActualMaximum(Calendar.DAY_OF_MONTH); // <-- the result!
Benoit Courtine
That's not Jodatime. The OP explicitly asked for this.
BalusC
Oups. Exact... I focused on the problem and forgot the title... But if the result can be obtained easily with the standard API, an external API like JodaTime is useless.
Benoit Courtine
@Benoit: I would personally stay *well* away from java.util.Calendar. Joda Time is a far, far superior API. For example, how confident are you about what that will do if you set it to February when `getInstance` returns the 31st of September? Oh, and don't forget that February is month 1...
Jon Skeet
+3  A: 

If you have a DateTime object which represents a value in the month, then it's pretty straightforward. You get the dayOfMonth property from that DateTime object and get the maximum value of the property. Here is a sample function:

public static int daysOfMonth(int year, int month) {
  DateTime dateTime = new DateTime(year, month, 14, 12, 0, 0, 000);
  return dateTime.dayOfMonth().getMaximumValue();
}
Erick Robertson
A: 

Yes, although it's not as pretty as it might be:

import org.joda.time.*;
import org.joda.time.chrono.*;
import org.joda.time.field.*;

public class Test {
    public static void main(String[] args) {
        GregorianChronology calendar = GregorianChronology.getInstance();
        DateTimeField field = calendar.dayOfMonth();

        for (int i = 1; i < 12; i++) {
            LocalDate date = new LocalDate(2010, i, 1, calendar);
            System.out.println(field.getMaximumValue(date));
        }
    }
}

Note that I've hard-coded the assumption that there are 12 months, and that we're interested in 2010. I've explicitly selected the Gregorian chronology though - in other chronologies you'd get different answers, of course. (And the "12 month" loop wouldn't be a valid assumption either...)

I've gone for a LocalDate rather than a DateTime in order to fetch the value, to emphasize (however faintly :) that the value doesn't depend on the time zone.

This is still not as simple as it looks, mind you. I don't know off-hand what happens if use one chronology to construct the LocalDate, but ask for the maximum value of a field in a different chronology. I have some ideas about what might happen, knowing a certain amount about Joda Time, but it's probably not a good idea :)

Jon Skeet