i have a template, with a var LINK and a data file, links.txt, with one url per line
how in bash i can substitute LINK with the content of links.txt?
if i do
#!/bin/bash
LINKS=$(cat links.txt)
sed "s/LINKS/$LINK/g" template.xml
two problem:
$LINKS has the content of links.txt without newline
sed: 1: "s/LINKS/http://test ...": bad flag in substitute command: '/'
sed is not escaping the // in the links.txt file
thanks