MySQL order by COUNT DISTINCT

Question

Hello I have a sql table:

2.8.7
2.8.3
2.8.2
2.8.7
2.8.5
2.8.7
2.8.7
2.8.5
2.6.0
2.8.3
2.6.4
2.6.3
2.8.4
2.8.0
2.6.3
2.8.5
2.8.5
2.8.5
2.6.0
2.8.2

How do I bring a unique value version sorted by the number of these versions?

At the exit I want to get the following:

2.8.5 5

2.8.7 4

2.6.0 2

2.6.3 2

2.8.2 2

2.8.3 2

2.8.4 2

2.6.4 1

2.8.0 1

ORDER BY count unique versions))

Sorry for my bad english

Answer 1

SELECT
  version,
  COUNT(*) AS num
FROM
  my_table
GROUP BY
  version
ORDER BY
  COUNT(*) DESC

Answer 2

SELECT version, COUNT(*) FROM tablename
GROUP BY version
ORDER BY COUNT(*) DESC;

or, alternate syntax

SELECT version, COUNT(*) FROM tablename
GROUP BY 1
ORDER BY 2 DESC;

Answer 3

select version, count(*) from sometable group by version order by count(*) desc;