Bash echo all array members when array is referenced as a variable in a loop

Question

The "echo" below is failing and I am too retarded to figure out why. I am simply trying to echo all of the array members in my loop.

#!/bin/bash
foo=bar1,bar2
for i in ${foo//,/" "}
do
declare -a ${i}='(null null null null)'
echo ${i[*]}
done

Thanks for any help!

Answer 1

Try eval "echo \${$i[*]}"

Why are you doing it this way? There is probably an easier and more direct way to do whatever your ultimate goal is. If you describe it, perhaps we can help you avoid the unnecessary complication.