create alias with argument

Question

I want an alias that produce folowing result:

$cd /home/ok

[clear screen]
/home/ok
total 452K
-rwx--x--x 1 user gigl  16K Oct  1 14:08 ok0
drwx------ 5 user gigl    0 Oct  1 14:02 ok1
drwx------ 5 user gigl    0 Oct  1 13:59 ok2
drwx------ 9 user gigl    0 Oct  1 14:01 ok3
-rw------- 1 user gigl   32 Sep 30 14:36 ok4

I did a script like

$cat ~/.cd.sh
#!/bin/bash
cd $1 && clear && pwd && ls -lh --color=auto

But it does not change the current dir. This is probably because in the script it will change the dir but when it goes back to bash I'm back in the dir I executed the script.

Any idea ?

Thanks, from answers I got something like that working great:

alias ls="clear && pwd && ls -lh --color=auto"
cd() { builtin cd "$1" && ls; }

Answer 1

Personally, I'd recommend writing a function rather than an alias loaded from your .bashrc or .bash_profile.

The function would look pretty much like what you've already got:

cdd () {
  cd "$1"
  clear
  pwd
  ls -lh --color=auto
}

I'm not positive why the alias causes you to go back, but I tested the function and it works.

Answer 2

Use a function instead, for example

mycd() { cd "${1?}" && clear && pwd && ls -lh --color=auto; }

Answer 3

I don't think you want && either. This will run each command simultaneously, iirc. You should use semicolons.