Is there any downside to using
typedef char bool;
enum boolean { false, true };
in C to provide a semantic boolean type?
Is there any downside to using
typedef char bool;
enum boolean { false, true };
in C to provide a semantic boolean type?
In C99, you should be using stdbool.h
, which defines bool
, true
, and false
.
Otherwise what you have is fine. Using just the enum may be a bit simpler, but if you really want to save space what you have works.
The downside of typedef char bool;
is that if you compile with a C99 implementation and happen to include <stdbool.h>
, this ends up as typedef char _Bool;
, which is wrong. Also, if you ever tried to compile the code as C++, you'd have issues (that's not necessarily a problem, but it could be).
It would probably better either to use <stdbool.h>
if your implementation provides one or to use a different name for the type, like BOOL
.
The short answer is: it's fine. It's particularly good if you needed to make large arrays of them, although I would be tempted to just use the C99 built-in1.
Since you asked "is there any downside..." I suppose I could remark that there have been important machines that did not actually have a character load instruction. (The Cray and initial DEC Alpha come to mind.) Machines in the future may suddenly go all minimal once again.
It will always be fast to load a standard integral type.
It will probably always be fast to load a single character.
1. See C99 6.2.5. There is a built-in type _Bool
. Then, if you include <stdbool.h>
(see C99 7.16) you get an alias, the more gracefully named bool
, and defines for true
and false
. If you use this it will clash with your typedef but I'm sure it would be an easy thing to fix.
I would suggest using a bit to represent true or false, rather than a character. A character uses 8 bits, We can set 1 for true and 0 for false with just 1 bit. That will be more memory efficient and also satisfies the purpose. (e.g) char flag:1;
Reference : http://en.wikipedia.org/wiki/Bit_field