what is $@ OR searching for an explaination of $@ in bash

Question

I reckon that the handle $@ in a shell script is an array of all arguments given to the script. Is this true?

i ask, because i normally use search engines to gather information, but I cant google for $@ and I have grewn too custom to easily getting served everything.

Answer 1

Yes. Please see the man page of bash ( the first thing you go to ) under Special Parameters

   Special Parameters
       The shell treats several parameters specially.  These parameters may only be referenced; assignment to them is not allowed.
       *      Expands to the positional parameters, starting from one.  When the expansion occurs within double quotes, it expands to a  sin-
              gle  word  with  the  value  of  each parameter separated by the first character of the IFS special variable.  That is, "$*" is
              equivalent to "$1c$2c...", where c is the first character of the value of the IFS variable.  If IFS is  unset,  the  parameters
              are separated by spaces.  If IFS is null, the parameters are joined without intervening separators.
       @      Expands  to  the  positional  parameters,  starting  from  one.  When the expansion occurs within double quotes, each parameter
              expands to a separate word.  That is, "$@" is equivalent to "$1" "$2" ...  If the double-quoted expansion occurs within a word,
              the  expansion  of  the  first  parameter is joined with the beginning part of the original word, and the expansion of the last
              parameter is joined with the last part of the original word.  When there are no positional parameters, "$@" and  $@  expand  to
              nothing (i.e., they are removed).