Hi,
In HTML:
<select name=site[new][fw][version]></select>
In jQuery, I've tried:
var fwvs=$('select[name=site\\[new]\\[fw]\\[version]]')
But fwvs.length return 0. What am I doing wrong?
Thanks
views:
31answers:
2
+2
A:
You should escape both opening ([) and closing (]) brackets. Check jquery selectors docs.
Nikita Rybak
2010-10-11 08:46:44
like : var fwvs=$('select[name=site\\[new\\]\\[fw\\]\\[version\\]]')
Haim Evgi
2010-10-11 08:52:11
As i commented above, this did not worked for me, I had to use \\\ instead
fabjoa
2010-10-11 08:56:14
+2
A:
Try this:
$('select[name="site[new][fw][version]"]')
The attribute selectors can take arguments as strings, wrapped in quotes (single or double, same as JavaScript). Usually these aren't used, but they are useful in this case.
Working example: http://jsfiddle.net/kobi/32SNS/
Kobi
2010-10-11 08:47:58
That worked! Also, triple escaping (\\\) worked when double (\\) failed for me. Double works fine when the array has no other arrays in it, i.e., site[new], but after then, it seems triple escaping must be used. But thanks Kobi, your way worked though! I'll mark it as answered as soon as SO let me do so :)
fabjoa
2010-10-11 08:54:42
@fabjoa - Thanks. The other method should work as well (you are describing a strange error - I'd expect 2 ` \\ ` or 4 ` \\\\ `, if the JS is in a higher-level string), but this is probably simpler.
Kobi
2010-10-11 08:58:20