Help needed in Demonstartion of BufferOverflow

Question

#include<stdio.h>

hijack(){

printf("Hijacked");

}

GetInput(){

char buffer[8];
gets(buffer);
puts(buffer);

}

int main(){

GetInput(); //19
return 0;
}

This is the code...

when i place a break point at line 19..

and see the stackpointer i get...

0xbffff7f8:     **0xbffff878**      0x0014bbd6      0x00000001      0xbffff8a4
0xbffff808:     0xbffff8ac      0x0012f858      0xbffff860      0xffffffff

The one n bold is stack top...

then after next instruction...i get..

0xbffff7e4:     0x0011e0c0      0x080484ab      0x0028aff4      0xbffff7f8
0xbffff7f4:     0x0804847f      **0xbffff878**      0x0014bbd6      0x00000001

0x0011e0c0---------------------> ?????????????????

0x080484ab && 0x0028aff4 -----> the char buffer of 8 bytes...

0xbffff7f8----------------------> the ebp register

0xbffff7f8---------------------->return address...

And when i replace the register address with the address o function "hijack" it gives me a segmentation fault..

i am running this on ubuntu server 10.04...with PAE NX disabled...i checked it..

root@ubuntu:~# /usr/bin/check-bios-nx --verbose
This CPU is not PAE capable, so it does not have NX.

Pls help....