Let a function "return" the super function?

Question

Hi,

Given is the following code:

function two() {
    return "success";
}

function one() {
    two();
    return "fail";
}

If you test the code by calling function one(), you will always get "fail".

The question is, how can I return "success" in function one() by only calling function two()?

Is that even possible?

Regards

Answer 1

function one() {
   return two();
}

Answer 2

function one() {    
    return two();
}

Answer 3

You can't make a function return from the function that called it in Javascript (or many other languages, afaik). You need logic in one() to do it. E.g.:

 function one() {
     return two() || "fail";
 }