How do I separately convert a struct timeval into two 32 bit variables?

Question

A struct timeval is 64 bit long. I need, for a project, to convert this long (struct timeval) into two 32 bit chunks, and put each chunk into a different variable. How do I do this? Thanx in advance.

Answer 1

uint32_t* values = &timevalstruct;

// depends on endianess

uint32_t v1 = values[0];
uint32_t v2 = values[1];

Answer 2

As an addition to leppie's answer:

union tvs
{
    struct timeval tv;
    struct ints {
        uint32_t v1;
        uint32_t v2;
    };
};

tvs t;
t.tv = timevalstruct;
uint32_t v1 = tv.ints.v1;
uint32_t v2 = tv.ints.v2;

if you dont want to deal with pointers.

Answer 3

See this : http://linux.die.net/man/2/gettimeofday

Can you use tv_sec and tv_usec fields of the timeval structure?

Answer 4

struct timeval tv;
...
uint32_t seconds = tv.tv_sec;
uint32_t micros = tv.tv_usec;

There you go, separated into 32-bit integers.