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31

answers:

1

It must be simple, but surprisingly I couldn't find an answer to this problem here or by trial-and-error.
I want to get values out of a matrix (according to some condition) and place the values into a vector. I also need the subscript indices of the matching values. There is a lot of data so for loops are out.

This is a correct (but iterative) answer:

[I,J] = find(A > 5);
values = zeros(numel(I),1);
for i=1:numel(I)
    values(i) = A(I(i),J(i));
end

I tried values = A(I,J) but this is n-by-n instead of n-by-1.

+6  A: 

You can implicitly treat the matrix like a vector (linear indexing):

I = find(A > 5);
values = A(I);

Note that you can do this more efficiently with logical indexing:

values = A(A > 5);
Oli Charlesworth
+1. logical indexing rules!
Jason S
I wonder if it's faster to use sub2ind and find or find (for the indices) and logical indexing...
reve_etrange

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