How can I know whether one number is a multiple of other number?

Question

I tried using 6%2, but its always giving the value as 2 and not 0. Why and how can I get a solution to this?

Answer 1

bool prime = PrimeTool.IsPrime(input_Number);
        if (!prime)
        {
            Console.Write("multiple of other number");
            Console.WriteLine(i);
        }

Answer 2

if(!(y%x))
{
...
}

In your case !(6%2) would return true.

(Answer very similar to the original in the question)

Answer 3

I'm asuming that you want to find out if Y=kX has integer values of k for a given X so that Y=5, X=3 fails (k is 5/3), but Y=6, X=2 passes (k is exactly 3). You are happy that k is either positive or negative.

That way, using Y remainder X == 0 is a good test. As an aside, be careful of negative remainders (e.g. Y % 2 == 1 as a test for oddness fails for negative numbers, use Y % 2 != 0 to be sure)

Code example in Java

public class Example {

  public static void main(String[] args) {
    System.out.println(isIntegerFactor(5,3));  // k is not an integer
    System.out.println(isIntegerFactor(6,3));  // k is 2
    System.out.println(isIntegerFactor(-6,-3)); // k is 2 
    System.out.println(isIntegerFactor(-6,3)); // k is -2
    System.out.println(isIntegerFactor(6,-3)); // k is -2
  }

  public static boolean isIntegerFactor(int y, int x) {
    return (y % x) == 0;
  }

}