(...) hibernate has created a table hibernate_sequences, but the column type for the sequence_next_hi_value is an int(11). I have some entities (I mean tables) that have an id field of type bigint(20), will that works ? 
Yest, this will work.
  and when my table reach the number of rows I am expecting? 
I'm not sure I understood that part. But if the question is about running out of numbers, here are some numbers from the JPA wiki book:
  
  
  One paranoid delusional fear that
  programmers frequently have is running
  out of sequence numbers. Since most
  sequence strategies just keep
  incrementing a number it is
  unavoidable that you will eventually
  run out. However as long a large
  enough numeric precision is used to
  store the sequence id this is not an
  issue. For example if you stored your
  id in a NUMBER(5) column, this would
  allow 99,999 different ids, which on
  most systems would eventually run out.
  However if you store your id in a
  NUMBER(10) column, which is more
  typical, this would store
  9,999,999,999 ids, or one id each
  second for about 300 years (longer
  than most databases exist). But
  perhaps your system will process a lot
  of data, and (hopefully) be around a
  very long time. If you store your id
  in a NUMBER(20) this would be
  99,999,999,999,999,999,999 ids, or one
  id each millisecond for about
  3,000,000,000 years, which is pretty
  safe.
  
  But you also need to store this id in
  Java. If you store the id in a Java
  int, this would be a 32 bit number ,
  which is 4,294,967,296 different ids,
  or one id each second for about 200
  years. If you instead use a long, this
  would be a 64 bit number, which is
  18,446,744,073,709,551,616 different
  ids, or one id each millisecond for
  about 600,000,000 years, which is
  pretty safe.
IMO, an int(11) with a default allocation size of 50 gives you some time.