Is it possible to append functions to a JS class that have access to the class's private variables?

Question

I have an existing class I need to convert so I can append functions like my_class.prototype.my_funcs.afucntion = function(){ alert(private_var);} after the main object definition. What's the best/easiest method for converting an existing class to use this method? Currently I have a JavaScript object constructed like this:

var my_class = function (){

 var private_var = '';
 var private_int = 0
 var private_var2 = '';
 [...]

 var private_func1 = function(id) {
  return document.getElementById(id);
 };

 var private_func2 = function(id) {
  alert(id);
 };

 return{
  public_func1: function(){

  },

  my_funcs: {
   do_this: function{

   },
   do_that: function(){

   }
  }
 }
}();

Unfortunately, currently, I need to dynamically add functions and methods to this object with PHP based on user selected settings, there could be no functions added or 50. This is making adding features very complicated because to add a my_class.my_funcs.afunction(); function, I have to add a PHP call inside the JS file so it can access the private variables, and it just makes everything so messy.

I want to be able to use the prototype method so I can clean out all of the PHP calls inside the main JS file.

Answer 1

Try declaring your "Class" like this:

var MyClass = function () {
    // Private variables and functions
    var privateVar = '',
        privateNum = 0,
        privateVar2 = '',
        privateFn = function (arg) {
            return arg + privateNum;
        };
    // Public variables and functions
    this.publicVar = '';
    this.publicNum = 0;
    this.publicVar2 = '';
    this.publicFn = function () {
        return 'foo';
    };
    this.publicObject = {
        'property': 'value',
        'fn': function () {
            return 'bar';
        }
    };
};

You can augment this object by adding properties to its prototype (but they won't be accessible unless you create an instance of this class)

MyClass.prototype.aFunction = function (arg1, arg2) {
    return arg1 + arg2 + this.publicNum;
    // Has access to public members of the current instance
};

Helpful?

Edit: Make sure you create an instance of MyClass or nothing will work properly.

// Correct
var instance = new MyClass();
instance.publicFn(); //-> 'foo'
// Incorrect
MyClass.publicFn(); //-> TypeError

Answer 2

Okay, so the way you're constructing a class is different than what I usually do, but I was able to get the below working:

var my_class = function() {
    var fn = function() {
        this.do_this = function() { alert("do this"); }
        this.do_that = function() { alert("do that"); }
    }
    return {
        public_func1: function() { alert("public func1"); },
        fn: fn,
        my_funcs: new fn()
    }
}
var instance    = new my_class();
instance.fn.prototype.do_something_else = function() { 
    alert("doing something else"); 
}
instance.my_funcs.do_something_else();

As to what's happening [Edited]:

• I changed your my_funcs object to a private method 'fn'
• I passed a reference to it to a similar name 'fn' in the return object instance so that you can prototype it.
• I made my_funcs an instance of the private member fn so that it will be able to execute all of the fn methods

Hope it helps, - Kevin

Answer 3

Maybe I'm missing what it is you're trying to do, but can't you just assign the prototype to the instance once you create it? So, first create your prototype object:

proto = function(){
    var proto_func = function() {
        return 'new proto func';
    };
    return {proto_func: proto_func};
}();

Then use it:

instance = new my_class();
instance.prototype = proto;
alert(instance.prototype.proto_func());