Process.Start does not recognize my executable file ?

Question

Currently I am using the below code to start my application (which is working):

ProcessStartInfo myApp = new ProcessStartInfo();
myApp.FileName = "cmd.exe";
myApp.Arguments = @"/K D:\dir\file.bin additional args to raise app";
myApp.WindowStyle = ProcessWindowStyle.Hidden;
myApp.CreateNoWindow = true;

try
{
    Process.Start(myApp);
}
catch (Exception ex)
{
    MessageBox.Show(ex.ToString());
}

But if possible I would like to call it directly, but since it is a .bin extension not recognized to any application (like txt is to notepad for example) Process.Start won't start it unless i use the cmd to call it.

What other way do I have to start my application directly without having to summon it from cmd ?

I can also start it with begin > run and start aswell:

start D:/my/path/file.bin additional args to raise app

Answer 1

1) You do not have to provide full path of the cmd.exe. System will be able to find it

2) It seems you are trying to run cmd.exe with parameters in order to run your bin file. This will not work.

3) What is the bin file? You can assign a default application to .bin file type. Alternatively, start the aplication runner with ProcessStartInfo and pass your .bin file.

4) Not sure if all applications wil happliy use "/" instead of "\" .

Answer 2

Hmm, this is all pretty odd. Renaming the file to .exe if it actually is an executable file seems the lower paint point. Try cmd.exe /c start /wait d:/my/path/file.bin args.

Answer 3

Have you tried setting...?

myApp.UseShellExecute = true;

... and using the .bin file as your filename?