How to add a sequence of classes to three objects in one

Question

I need to add:

• an ID to the table in my form
• a numbered sequence of classes to a certain amount of TD's in every next TR in that table (three td's in this case)

I've got next html-model:

<form id="myform">
<table>
 <tr>
  <td>some text</td>
  <td>some text</td>
  <td>some text</td>
</tr>
 <tr>
  <td>some text</td>
  <td>some text</td>
  <td>some text</td>
</tr>
</table>
</form>

I need that to be like this after jquery applied:

<form id="myform">                   <!--no changes-->
 <table id="table1">                 <!--changed-->
  <tr>       
   <td class="td1">some text</td>    <!--changed-->
   <td class="td2">some text</td>    <!--changed-->
   <td class="td3">some text</td>    <!--changed-->
  </tr>
  <tr>       
   <td class="td1">some text</td>    <!--changed-->
   <td class="td2">some text</td>    <!--changed-->
   <td class="td3">some text</td>    <!--changed-->
  </tr>
 </table>
</form>

Thanks in advance

Answer 1

Here the code you want to add in your script

$("#myform table").attr("id", "table1");

$("#myform table tr").each(function(){
    $("td:eq(0)",$(this)).attr("id", "td1");
    $("td:eq(1)",$(this)).attr("id", "td2");
    $("td:eq(2)",$(this)).attr("id", "td3");
});

Answer 2

Let's try:

$(function(){
    $('#myform').find('table').each(function(i,e){
       var $table = $(e);

       $table.attr('id', 'table' + (parseInt($table.index(),10)+1));

       $table.find('tr').each(function(i2,e2){
          var $tr = $(e2);

          $tr.find('td').each(function(i3, e3){
             var $td = $(e3);

             $td.addClass('td' + (parseInt($td.index(),10)+1));
         });
       });
    });
});

Example: http://www.jsfiddle.net/YjC6y/43/

This should work pretty generic. Anyway I'm not sure if that is the best way to do it, but I'm sure the elegant & clever people at Stackoverflow will correct this if not.

Answer 3

(function($) {
    var id = 'myid';
    var class_prefix = 'myclass-';
    $("#myform").find('table')
    .attr('id', id)
    .find('tr').each(function(i,el) {
        row = $(el);
        row.children('td').each(function(k, col) {
            $(col).addClass(class_prefix + k);
        });
    }); 
});

Answer 4

$('#myform table').each(function(i, v) {
   $(v).attr('id','table' + (i + 1)).find('tr').each(function(idx, val) {
        $(val).children().each(function(index,element) {
            $(element).addClass('td' + (index + 1));
        });
   });
});