I have this:
List<string> fields;
fields[0] = "firstFieldName";
fields[1] = "secondFieldName";
...
fields[n] = "nthFieldName";
I want to get this:
var selector = p => new {p.firstField, p.secondField, ..., p.nthFieldName}
// selector is of type Expression<Func<Entity, object>>
GoofBallLogic had this code that was simliar, ending up with p => p.column
// Entity is an object in a diagram from Entity Framework 4
var p = Expression.Parameter(typeof(Entity, "p");
var selector = Expression.Lambda<Func<Entity, string>(
Expression.Property(p, columnToGroupBy), p );
EDIT: What I am trying to accomplish
I have a "generic" Repository:
public class Repository<E, C> : IRepository<E,C>
{
private C _dc {get;set;} // ObjectContext (Entity Framework 4)
private string _entityName {get;set;}
public string entityKeyName {get;private set;}
public List<string> entityKeys {get;private set;}
public Expression<Func<E, object>> entityKey {get;private set;}
private EntityContainer _containerName {get;set;}
public Repository(C myDC)
{ _dc = myDC; // TODO: check for null
// Name of "this" ObjectContext
_containerName = _dc.MetadataWorkspace.GetEntityContainer(
_dc.DefaultContainerName, DataSpace.CSpace);
// Name of "this" Entity
_entityName = _containerName.BaseEntitySets
.Where(p => p.ElementType.Name == typeof (E).Name)
.Select( p => p.Name).FirstOrDefault();
// String list of the keys
entityKeys = _containerName
.BaseEntitySets.First(meta => meta.ElementType.Name ==
typeof(E).Name)
.ElementType.KeyMembers.Select(k => k.Name).ToList();
// Thanks Jon Skeet for this cool comma sep list formula
entityKeyName = string.Join(",", entityKeys.ToArray() );
entityKey = Expression.Lambda<Func<E, object>> ...
What to do to set entityKey as an object that can be used in an OrderBy statement since Linq to Entities requires ordering a set before doing a .Skip().Take()
Edit:
Amazingly, Orderby can take this:
p => "field1,field2,field3"
Which allows my code to execute but doesn't actually order the items by the field values. It's a first step in TDD I guess: use a literal.