Hi Guys, I have a textbox for 'Area '.I need a regularexpression to validate textbox such that it should allow decimals to enter but no characters.Anyone can help me
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8918answers:
9Don't forget - he also wants decimal '.' character
Marc Novakowski
2009-01-05 08:19:10
That can also be a comma "," depending on what country you live in.
some
2009-01-05 08:35:19
A:
If you want decimals, this should work:
/^(?:\d+\.?)|(?:\d*\.\d+)$/
Ben Alpert
2009-01-05 08:19:54
+1
A:
What is the format of your decimal numbers you will support in your field ?
This "Simple Regular expression for decimal numbers?" StackOverflow question details the possible regex.
^\d+(\.\d{1,2})?$
Can ensure a number with one or two decimals, but would not work with 34. (dot without decimal)
You have lots of possible regex listed here.
Unkwntech is a good complete regexp but would allow 1,15223,11,00.
I would rather use:
[-+]?(?:\d(\,?(?>\d{3}[.,]))?)*(?:\.\d*)?
Meaning, if you are using a ,, do so only if it is followed with 3 digits (and then another , or a dot for decimal values. That enforces digital grouping, even though, as pointed out by Paul in the comments, there are locale with more than three digits after a comma...
VonC
2009-01-05 08:21:20
+1
A:
This regex can validate integers and optional floating point numbers:
[0-9]*.?[0-9]+
And instead of using regular expressions, you could use isNaN(value) to check if the numerical value is not a number (NaN).
CMS
2009-01-05 08:21:38
A:
For decimal values you would have to allow [.] as well so this should work for you :
^[-+]?\d*.?\d*$
(this would also accept + and - symbols)
You can get more specific expression from the RegExLib here :
Jomit
Jomit
2009-01-05 08:22:57
+1
A:
How about
[-+]?(?:\d\,?){0,}(?:\.\d*)?
It will match all the following exapmles that have a *:
0*
0.0*
222.0*
1,000.00*
100,000.00*
-100,000,000,000.12*
asdf
blah.blah
Unkwntech
2009-01-05 08:25:48
You can use ? instead of {0,1} to speed up parsing and make the regexp easier to read.
strager
2009-01-05 08:48:49
-1 for it would allow 1,04400.00 (more than three digits after a ','). See my completed answer for a more robust regex
VonC
2009-01-05 09:01:33
I think it's better to just strip the , anyway as they likely will be irrelivent to the actual use anyway.
Unkwntech
2009-01-05 09:13:37
+4
A:
Why not try something that's already built-in to JavaScript: the parseFloat function?
Zach Hirsch
2009-01-05 09:00:45
because parseFloat allows all kinds of invalid input that you don't want to see.
eplawless
2009-01-05 09:13:39
Do you mean that parseFloat("123 foo") == 123 ? Then couldn't you just reject the string if there's whitespace in it?
Zach Hirsch
2009-01-05 09:25:49
@Hirsch, Then parseFloat("123foo") would workfine, I think. Still, +1, for stealing my answer. ;P
strager
2009-01-05 18:05:36