I have a long sequence of hex digits in a string, such as
000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44
only much longer, several kilobytes. Is there a builtin way to convert this to a bytes object in python 2.6/3?
views:
3864answers:
3
+8
A:
Try the binascii module
from binascii import unhexlify
bytes = unhexlify(myhexstr)
Crescent Fresh
2009-01-14 17:46:38
Two ways to do it in 2.x, three ways in 3.x. So much for "there's only one way to do it"...
technomalogical
2009-01-14 18:58:50
Other two ways are more 'built-in' so I would actually use one of those.
Crescent Fresh
2009-01-14 19:17:31
@technomalogical: your comment is irrelevant to the answer; perhaps you should delete it and change it into a post to comp.lang.python .
ΤΖΩΤΖΙΟΥ
2009-01-15 13:51:19
@technomalogical: I agree with ΤΖΩΤΖΙΟΥ. Also, you got it wrong. The correct phrase is: There should be one-- and preferably only one --*obvious* way to do it.
nosklo
2009-01-16 11:40:53
+10
A:
You can do this with the hex codec. ie:
>>> s='000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44'
>>> s.decode('hex')
'\x00\x00\x00\x00\x00\x00HB@\xfa\x06=\xe5\xd0\xb7D\xad\xbe\xd6:\x81\xfa\xea9\x00\x00\xc8B\x86@\xa4=P\x05\xbdD'
Brian
2009-01-14 17:47:20