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9638

answers:

7

I use a datepicker for choosing an appointment day. I already set the date range to be only for the next month. That works fine. I want to exclude Saturdays and Sundays from the available choices. Can this be done? If so, how?

+39  A: 

There is the beforeShowDay option, which takes a function to be called for each date, returning true if the date is allowed or false if it is not. From the docs:


beforeShowDay

The function takes a date as a parameter and must return an array with [0] equal to true/false indicating whether or not this date is selectable and [1] equal to a CSS class name(s) or '' for the default presentation. It is called for each day in the datepicker before is it displayed.

Display some national holidays in the datepicker.

$(".selector").datepicker({ beforeShowDay: nationalDays})   

natDays = [
  [1, 26, 'au'], [2, 6, 'nz'], [3, 17, 'ie'],
  [4, 27, 'za'], [5, 25, 'ar'], [6, 6, 'se'],
  [7, 4, 'us'], [8, 17, 'id'], [9, 7, 'br'],
  [10, 1, 'cn'], [11, 22, 'lb'], [12, 12, 'ke']
];

function nationalDays(date) {
    for (i = 0; i < natDays.length; i++) {
      if (date.getMonth() == natDays[i][0] - 1
          && date.getDate() == natDays[i][1]) {
        return [false, natDays[i][2] + '_day'];
      }
    }
  return [true, ''];
}

One built in function exists, called noWeekends, that prevents the selection of weekend days.

$(".selector").datepicker({ beforeShowDay: $.datepicker.noWeekends })


To combine the two, you could do something like (assuming the nationalDays function from above):

$(".selector").datepicker({ beforeShowDay: noWeekendsOrHolidays})   

function noWeekendsOrHolidays(date) {
    var noWeekend = $.datepicker.noWeekends(date);
    if (noWeekend[0]) {
        return nationalDays(date);
    } else {
        return noWeekend;
    }
}
Adam Bellaire
Thanks for this, couldn't find this method in the docs anywhere.
Neil Aitken
excellent solution. particularly like how concise your explanation is. @Neil: http://dev.jqueryui.com/ticket/5851
Kaushik Gopal
+7  A: 

If you don't want the weekends to appear at all, simply:

CSS

th.ui-datepicker-week-end,
td.ui-datepicker-week-end {
    display: none;
}
A: 

I get an error that natDays is not defined.

natDays = [ [5, 4, 'us'], [8, 17, 'id'], [9, 7, 'br'], [10, 1, 'cn'], [11, 22, 'lb'], [12, 12, 'ke'] ];

 function nationalDays(date) {
  for (i = 0; i < natDays.length; i++) {
    if (date.getMonth() == natDays[i][0] - 1
     && date.getDate() == natDays[i][1]) {
   return [false, natDays[i][2] + '_day'];
    }
  }
   return [true, ''];
 }


 $("#datepickerthing").datepicker({ beforeShowDay: noWeekendsOrHolidays})   

 function noWeekendsOrHolidays(date) {
  var noWeekend = $.datepicker.noWeekends(date);
  if (noWeekend[0]) {
   return nationalDays(date);
  } else {
   return noWeekend;
  }
 }
+1  A: 

In this version, month, day, and year determines which days to block on the calendar.

$(document).ready(function (){
  var d         = new Date();
  var natDays   = [[1,1,2009],[1,1,2010],[12,31,2010],[1,19,2009]];

  function nationalDays(date) {
    var m = date.getMonth();
    var d = date.getDate();
    var y = date.getFullYear();

    for (i = 0; i < natDays.length; i++) {
      if ((m == natDays[i][0] - 1) && (d == natDays[i][1]) && (y == natDays[i][2]))
      {
        return [false];
      }
    }
    return [true];
  }
  function noWeekendsOrHolidays(date) {
    var noWeekend = $.datepicker.noWeekends(date);
      if (noWeekend[0]) {
        return nationalDays(date);
      } else {
        return noWeekend;
    }
  }
  $(function() { 
    $(".datepicker").datepicker({

      minDate: new Date(d.getFullYear(), 1 - 1, 1),
      maxDate: new Date(d.getFullYear()+1, 11, 31),

      hideIfNoPrevNext: true,
      beforeShowDay: noWeekendsOrHolidays,
     });
  });
});
Christopher Altman
A: 
neo
A: 

Hi Neo,

Thanks for your code !!

Is there a way so that you can exclude for instance, Mondays & Wednesdays? or it has to be only Saturdays & Sunday?

thanks Sebastian

Sebastian
+1  A: 

These answers were very helpful. Thank you.

My contribution below adds an array where multiple days can return false (we're closed every Tuesday, Wednesday and Thursday). And I bundled the specific dates plus years and the no-weekends functions.

If you want weekends off, add [Saturday], [Sunday] to the closedDays array.

$(document).ready(function(){

    $("#datepicker").datepicker({
        beforeShowDay: nonWorkingDates,
        numberOfMonths: 1,
        minDate: '05/01/09',
        maxDate: '+2M',
        firstDay: 1
    });

    function nonWorkingDates(date){
        var day = date.getDay(), Sunday = 0, Monday = 1, Tuesday = 2, Wednesday = 3, Thursday = 4, Friday = 5, Saturday = 6;
        var closedDates = [[7, 29, 2009], [8, 25, 2010]];
        var closedDays = [[Monday], [Tuesday]];
        for (var i = 0; i < closedDays.length; i++) {
            if (day == closedDays[i][0]) {
                return [false];
            }

        }

        for (i = 0; i < closedDates.length; i++) {
            if (date.getMonth() == closedDates[i][0] - 1 &&
            date.getDate() == closedDates[i][1] &&
            date.getFullYear() == closedDates[i][2]) {
                return [false];
            }
        }

        return [true];
    }




});
orolo
You could just edit your old answer, instead of posting a brand new one - include both in the same answer, given how similar they are, or simply delete the old one and leave the better version
Yi Jiang